Question

Find the de Broglie wavelength of electrons moving with a speed of $7\times {10}^{6}m{s}^{-1}$.

Answer 1

Velocity of electron $v=7\times {10}^{6}m/s$

de Broglie wavelength $\lambda =\frac{h}{mv}$

$\therefore$ $\lambda =\frac{6.6\times {10}^{-34}}{(9.1\times {10}^{-31})(7\times {10}^6)}=0.104\times {10}^{-9}m=1.04$ Angstrome