Question

Find the degree of the following polynomial.
$\sqrt{3}{x}^3+19x+14$

Answer 1

In the given polynomial $\sqrt{3}{x}^3+19x+14$, the exponents of the variable $x$ are $3$ and $1$.

We know that the highest exponent of the variable $x$ is the degree of the polynomial.

Hence, the degree of the polynomial $\sqrt{3}{x}^3+19x+14$ is $3$.