Question

Find the derivate of $e^{\sqrt{2x+1}}$ with respect to $x$ at $x=12$

Answer 1

$\frac{d}{dx}\left(e^{\sqrt{2x+1}}\right)$ at $x=12$

$\frac{d}{dx}\left(e^{\sqrt{2x+1}}\right)=\left(e^{\sqrt{2x+1}}\right).\frac{1}{2\sqrt{2x+1}}.2$

$=\frac{e^{\sqrt{2x+1}}}{\sqrt{2x+1}}$

at $x=12,\frac{e^{\sqrt{2x+1}}}{\sqrt{2x+1}}=\frac{e^{\sqrt{25}}}{\sqrt{25}}$

$=\frac{1}{5}{e}^5$