Question

Find the derivative of the following function:
f(x) = $cosecxcotx$

Answer 1

Here $f\left(x\right)=cosescxcotx$

$\therefore f^{\prime }\left(x\right)=\frac{d}{dx}\left[cosescxcotx\right]$

$=cosecx\frac{d}{dx}\left(cotx\right)+cotx\frac{d}{dx}\left(cosecx\right)$

$=cosecx(-cose{c}^{2}x)+cotx(-cosecxcotx)$

$=-cose{c}^{3}x-cosecxco{t}^{2}x$