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Question

Find the derivative of the following function:
f(x)= ax+b(px2+qx+r)

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Solution

Here f(x)=ax+bpx2+qx+r

f(x)=(px2+qx+r)ddx(ax+b)(ax+b)ddx(px2+qx+r)(px2+qx+r)2=(px2+qx+r)(a)(ax+b)(2px+q)(px2+qx+r)2

=apx2+aqx+ar2apx2=aqx2bpxbq(px2+qx+r)2

=apx22bpx+arbq(px2+qx+r)2

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