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Question

Find the derivative of the following
(i) xxn+xnx
(ii) logx2+1

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Solution

(i) y=xxn+xnx

y=xn(xxn1)nxn1+nxxnx1nxlnn

(ii)y= logx2+1

y=1x2+1×2x2x2+1
y=xx2+1

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