CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the derivative of y(x)=x3(x+1)2 with respect to x.

A
2x2(x+1)22x3(x+1)3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
3x2(x+1)22x3(x+1)3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
3x2(x+1)2+2x3(x+1)3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3x2(x+1)23x3(x+1)3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 3x2(x+1)22x3(x+1)3
We can rewrite this function as y(x)=x3(x+1)2 and apply product rule,
dydx=(x+1)2ddx(x3)+x3ddx(x+1)2dydx=(x+1)2.3x2+x3(2)(x+1)3dydx=3x2(x+1)22x3(x+1)3

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon