Question

Find the derivatives of
${\sin }^{2}x$

Answer 1

Let $y={\sin }^{2}x$

$\frac{dy}{dx}=2\sin x\frac{d}{dx}\left(\sin x\right)$

$\frac{dy}{dx}=2\sin x\cos x\frac{d}{dx}\left(x\right)$

$\frac{dy}{dx}=2\sin x\cos x\times 1$

$\therefore \frac{dy}{dx}=2\sin x\cos x=\sin 2x$