Question

Find the $\frac{dy}{dx}$ by implicit differentiation. $x^2-8xy+y^2=8$

Answer 1

$x^2-8xy+y^2=8$

Now differentiating both sides with respect to $x$ we get,

$2x-8y+(-8x+2y)\frac{dy}{dx}=0$

or, $\frac{dy}{dx}=\frac{8y-2x}{2y-8x}$