Question

Find the discriminant for the given quadratic equation:

$\sqrt{3}{x}^2+2\sqrt{2}x-2\sqrt{3}=0$

• A. $26$
• B. $32$
• C. $38$
• D. $44$

Answer 1

The correct option is B $32$

Given equation is,

$\sqrt{3}{x}^2+2\sqrt{2}x-2\sqrt{3}=0$
We know, $D=b^2-4ac$
$a=\sqrt{3},b=2\sqrt{2},c=-2\sqrt{3}$

$D=(2\sqrt{2}{)}^2-4\times \sqrt{3}\times (-2\sqrt{3})$
$D=8+24$
$\therefore D=32$