Find the distance between the following pair of points- asin-bcos- and acos-bsin-

The correct option is A ( sinα #160; cosα ) ×√(a^2+b^2) Given, #160; (x_1,y_1) = (asinα, bcosα) and #160; (x_2,y_2) = (a ...

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Integration by Parts

Find the dist...

Question

Find the distance between the following pair of points:
$(a sin α, - b cos α)$ and $(a cos α, - b sin α)$

(

sin α

cos α

)

\times \sqrt{a^{2} + b^{2}}

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(

sin α

cos α

)

\times \sqrt{a^{2} + b^{2}}

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(

sin α

cos α

)

\times \sqrt{a^{2} - b^{2}}

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(

sin α

cos α

)

\times \sqrt{a^{2} - b^{2}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

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Solution

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Similar questions

s i n α + s i n β = a

c o s α + c o s β = b,

s i n (α + β) = \frac{2 a b}{a^{2} + b^{2}}

c o s (α + β) = \frac{b^{2} - a^{2}}{b^{2} + a^{2}}

If $s i n α + s i n β = a a n d c o s α + c o s β = b$ , prove that

(i) $s i n (α + β) = \frac{2 a b}{a^{2} + b^{2}}$

(ii) $c o s (α - β) = \frac{a^{2} + b^{2} - 2}{2}$

sin α + sin β = a

cos α + cos β = b

tan \frac{α - β}{2} = \pm \sqrt{\frac{x - a^{2} - b^{2}}{a^{2} + b^{2}}}

x

sin α + sin β = a

cos α + cos β = b

sin α + β = \frac{m a b}{a^{2} + b^{2}}

m

a x^{2} + b x + c = 0,

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