find the distance of a point (3/5,4/5) from the point of intersection of x- axis and y- axis

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Solution

$We know that x - axis and y - axis intersect at the origin (0, 0) . Now, know that distance between the points (x_{1}, y_{1}) and (x_{2}, y_{2}) is distance = \sqrt{{(x_{2} - x_{1})}^{2} + {(y_{2} - y_{1})}^{2}} Now, distance between the points (\frac{3}{5}, \frac{4}{5}) and (0, 0) is distance = \sqrt{{(\frac{3}{5} - 0)}^{2} + {(\frac{4}{5} - 0)}^{2}} = \sqrt{\frac{9}{25} + \frac{16}{25}} = \sqrt{\frac{25}{25}} = 1 unit$

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