Question

Find the distance of the point P (4, 3) from the origin?

Answer 1

The point P(4,3) is shown in the graph given below:


Since $△$ OAP is right angled triangle where

OA = 4 units

AP = 3 units

By using Pythagoras theorem:

$OP=\sqrt{O{A}^2+A{P}^2}$

$=\sqrt{4^2+3^2}$

$=\sqrt{16+9}$

$=\sqrt{25}$

= 5 units

Thus the distance of the point P(4,3) from the origin is 5 units.