Find the E0cell for the following cell reaction- Fe-2-Zn - Zn-2 - FeGiven- E0Zn-Zn-2 - 0-76V- E0Fe-Fe-2 - -0-41V

E _ cell =E_ red + E _ oxid #160; #160; #160; #160; #160; = E _ Fe ^ 2+ /Fe + E _ Zn/ Zn ^ 2+ #160; #160; #160; #160; #16 ...

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Electrochemical Cells, Galvanic Cells

Find the E0...

Question

Find the $E_{c e l l}^{0}$ for the following cell reaction:
$F e^{= 2} + Z n \to Z n^{+ 2} + F e$
Given, $E_{Z n / Z n^{+ 2}}^{0} = 0.76 V, E_{F e / F e^{+ 2}}^{0} = + 0.41 V$

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Solution

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E^{o}

Z n ⟶ {Z n}^{2 +} + 2 e^{-}

E^{o} = + 0.76 V

F e ⟶ {F e}^{2 +} + 2 e^{-}

E^{o} = + 0.41 V

{F e}^{2 +} + Z n ⟶ {Z n}^{2 +} + F e

E^{o}

Z n \to {Z n}^{2 +} + 2 e^{-}; E^{o} = + 0.76 V

F e \to {F e}^{2 +} + 2 e^{-}; E^{o} = + 0.41 V

{F e}^{2 +} + Z n \to {Z n}^{2 +} + F e

Z n \to Z n^{2 +} + 2 e^{-} (E_{(Z n^{2 +} / Z n)}^{0} = - 0.76 V)

F e \to F e^{2 +} + 2 e^{-} E^{0} = 0.41 V

F e^{2 +} + Z n \to Z n^{2 +} + F e

E^{⊝}

Z n \to Z n^{2 +} + 2 e^{-}; E^{⊝} = + 0.76 V

F e \to F e^{2 +} + 2 e^{-}; E^{⊝} = 0.41 V

F e^{2 +} Z n \to Z n^{2 +} + F e

E^{o}

Z n \to Z n^{2 +} + 2 e^{-}; E^{o} = - 0.76 V

F e^{2 +} + 2 e^{-} \to F e; E^{o} = + 0.41 V

F e^{2 +} + Z n \to Z n^{2 +} + F e

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