wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the eccentricity of the hyperbola x2a2y2b2=1 which passes through (4,0) & (32,2)

A
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 3
Since, given hyperbola passes through (4,0) & (32,2)
16a20b2=1a2=16
And 18164b2=1b2=32
Hence, required eccentricity is =1+b2a2=3

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Rectangular Hyperbola
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon