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Question

Find the electric current drawn from the battery of emf 12 V.


A
1 A
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B
4 A
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C
2 A
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D
3 A
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Solution

The correct option is C 2 A
Let current I3 is drawn from the battery of 12 V.
This is divided into 2 streams of current I1 and I2.
With help of kirchhoff's law on junction E
I3 = I1 + I2

Using the loop law,
For the loop EADFE, starting from a 12 V battery and going anti-clockwise.
Loop EADFA
Applying KVL , from 12V battery
1252I13(I1+I2)=0
72I13I13I2=0
75I13I2=0
5I1+3I2=7 ……..(1)

Using the loop law,
For the loop EBCFE, starting from a 12 V battery and going clockwise.

Loop EBCFE
Applying KVL , from 12V battery
124I23(I1+I2)=0
124I23I13I2=0
123I17I2=0
3I1+7I2=12 …….(2)

Solving eq (1) and eq(2)
3(5I1+3I2=7)=>15I1+9I2=21
5(3I1+7I2=12)=>15I1+35I2=60
26×I2=39
I2=1.5 A putting this in eq (1)
5I1+3×1.5=7
5I1=2.5
I1=0.5 A

I3=I1+I2=0.5 A+1.5 A=2 A

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