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Question

Find the equation for the ellipse that satisfies the given conditions,
Ends fo major axis (±3,0) ends of minor axis (0,±2)

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Solution

Ends of major axis (±3,0)lie on x. axis. So the equation of ellipse in standard form is,(x2a2+y2b2)=1
Now ends fo major axis (±a,0)is(±3,0)
a=3
Ends fo minor axis (0,±b)is(0,±2)b=2 Thus equation of required ellipse is,
x29+y24=1.


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