Question

Find the equation of a line drawn perpendicular to the line $\frac{x}{4}+\frac{y}{6}=1$ through the point, where it meets the y-axis.

Answer 1

Point on the $y-axis=(0,6)$

and line perpendicular to $\frac{x}{4}+\frac{y}{6}=1$

$⟹y=\frac{4}{6}x+c$

As it passes through the point $(0,6)$ . Hence, the equation $c=6$

$y=\frac{4}{6}x+6$