Question

Find the equation of a line whose inclination is ${30}^{\circ }$ and making an intercept of -3/5 on the y-axis

• A. $y=\frac{5}{\sqrt{6}}x+\frac{2}{5}$
• B. $y=\frac{1}{\sqrt{3}}x-\frac{3}{5}$
• C. $y=\frac{3}{\sqrt{7}}x-\frac{1}{3}$
• D. $\frac{-5}{3}x$

Answer 1

The correct option is B $y=\frac{1}{\sqrt{3}}x-\frac{3}{5}$

The equation of any straight line can be written as $y=mx+c$, where $m$ is its slope and $c$ is its y - intercept.
As inclination is ${30}^o$, slope of the line $=tan\left({30}^o\right)=\frac{1}{\sqrt{3}}$
So equation of line is $y=\frac{1}{\sqrt{3}}x-\frac{3}{5}$