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Question
Find the equation of a straight line:
(i) with slope 2 and y-intercept 3; (ii) with slope -1/3 and y-intercept -4.
(iii) with slope -2 and intersecting the x-axis at a distance of 3 units to the left of origin.
Find the equation of a straight line:
(i) with slope 2 and y-intercept 3; (ii) with slope -1/3 and y-intercept -4.
(iii) with slope -2 and intersecting the x-axis at a distance of 3 units to the left of origin.
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Solution
(i) with slope 2 and y-intercept 3m = 2, point is (0, 3)The required equation of line isy=mx+c⇒ y=2x+3(ii) Slope=−13,y intercept=(0, −4)m=−13, c=−4The required equation of line isy=mx+c⇒ y=−13x−4⇒ 3y+x=−12x+3y+12=0(ii) m=−2, c=−3The required equation of line isy−y1=m(x−x1)Since the line cuts the x-axis at (-3, 0) with slope -2, we have,y−0=−2(x+3)⇒ y=−2x−6⇒ 2x+y+6=0
(i) with slope 2 and y-intercept 3m = 2, point is (0, 3)The required equation of line isy=mx+c⇒ y=2x+3(ii) Slope=−13,y intercept=(0, −4)m=−13, c=−4The required equation of line isy=mx+c⇒ y=−13x−4⇒ 3y+x=−12x+3y+12=0(ii) m=−2, c=−3The required equation of line isy−y1=m(x−x1)Since the line cuts the x-axis at (-3, 0) with slope -2, we have,y−0=−2(x+3)⇒ y=−2x−6⇒ 2x+y+6=0
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