Question

Find the equation of a straight line passing through $(-1,2)$ and whose slope is $\frac{2}{5}$ .

Answer 1

We have,

$slope=\frac{2}{5}$

$Point=(-1,2)$

We know that the equation of a straight line passing through a point

$y-y_1=m(x-x_1)$

$y-2=\frac{2}{5}(x+1)$

$5y-10=2x+2$

$2x-5y+12=0$

Hence, this is the answer.