Question

Find the equation of the straight line passing through $(-4,5)$ and having slope $\frac{-2}{3}$

Answer 1

Given:Slope$=\frac{-2}{3}$

Point is $(-4,5)$

Equation of the line is $y-y_1=m(x-x_1)$

$y-5=\frac{-2}{3}(x+4)$

$\Rightarrow 3y-15=-2x-8$

$\Rightarrow 3y-15+2x+8=0$

$\therefore$Equation of the line is $2x+3y-7=0$