Question

Find the equation of a straight line passing through the points $(-3,-6)$ and $(2,5)$

Answer 1

Equation of the line is $\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}$

$\Rightarrow \frac{y+6}{x+3}=\frac{5+6}{2+3}$

$\Rightarrow \frac{y+6}{x+3}=\frac{11}{5}$

$\Rightarrow 5y+30=11x+33$

$\Rightarrow 11x-5y+33-30=0$

$\therefore$ Equation of a line is $11x-5y+3=0$