Question

Find the equation of a straight line whose inclination is ${60}^{\circ }$ and $y-$ intercept is $-3$

Answer 1

Given:$\theta ={60}^{\circ },y$-intercept$=-3$

Slope$m=\tan \theta =\tan {60}^{\circ }=\sqrt{3}$

Equation of a line is $y=mx+c$

$y=\sqrt{3}x-3$

$\Rightarrow y=\sqrt{3}x-3$

Equation of line is $\sqrt{3}x-y-3=0$