Find the equation of a straight line whose slope is $- 3$ and y-intercept is $4$ .

3 x + y - 4 = 0

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3 x + y + 4 = 0

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3 x - y - 4 = 0

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None of these

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Solution

The correct option is A $3 x + y - 4 = 0$
We have,
$m = - 3$ and $c = 4$
$y = m x + c$

$y = - 3 (x) + 4$

$y - 4 = - 3 x$

$3 x + y - 4 = 0$

Hence, this is the answer.

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Find the equation of a straight line whose slope is −3 and y-intercept is 4.

The correct option is A 3x+y−4=0We have,m=−3 and c=4y=mx+cy=−3(x)+4y−4=−3x3x+y−4=0Hence, this is the answer.

Find the equation of a straight line whose slope is $- 3$ and y-intercept is $4$ .

The correct option is A $3 x + y - 4 = 0$
We have,
$m = - 3$ and $c = 4$
$y = m x + c$

$y = - 3 (x) + 4$

$y - 4 = - 3 x$

$3 x + y - 4 = 0$

Hence, this is the answer.