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Question

Find the equation of a straight line with slope – 1/ 3 and y – intercept – 4.

A
3y + x = -12
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B
3y + x = -12
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C
2y + x = 12
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D
3y + x = 12
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Solution

The correct option is B 3y + x = -12

The slope is – 1/3 and the coordinates are (0, – 4)

Now, the required equation of line is

y = mx + c

Substitute the values, we get

y = -1/3x – 4

3y + x = – 12


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