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Byju's Answer
Standard XII
Mathematics
Equation of Circle with (h,k) as Center
Find the equa...
Question
Find the equation of circle on which the co-ordinates of any point are
(
2
+
4
c
o
s
θ
,
−
1
+
4
s
i
n
θ
)
,
θ
being the parameter.
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Solution
x
=
2
+
4
c
o
s
θ
,
y
=
−
1
+
4
s
i
n
θ
clearly
(
x
−
2
)
2
+
(
y
+
1
)
2
=
16
(
c
o
s
2
θ
+
s
i
n
2
θ
)
=
16
Above represents a circle with centre
(
2
,
−
1
)
and radius
4
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Similar questions
Q.
Find the equation of the circle with parametric co-ordinates
x
=
−
3
+
4
cos
θ
,
y
=
4
+
4
sin
θ
.
Q.
Circle on which the coordinates of any point are
(
2
+
4
cos
θ
,
−
1
+
4
sin
θ
)
where
θ
is the parameter is given by
(
x
−
2
)
2
+
(
y
+
1
)
2
=
16
.
Q.
Find the equation of the circle :
(a) centered at
(
3
,
−
2
)
with radius
4
(b) with end points of the diameter as
(
2
,
−
1
)
and
(
3
,
2
)
(c) with parametric co-ordinates
x
=
−
3
+
4
cos
θ
,
y
=
4
+
4
sin
θ
(d) passing through three points
(
0
,
2
)
,
(
3
,
0
)
and
(
3
,
2
)
Q.
Find the parametric equation of the circle
x
2
+
y
2
−
2
x
+
4
y
−
11
=
0
Q.
Assertion :consider
Δ
ABC whose verticies are A = (3 + 4 cos
Θ
,
−
5
+
4
s
i
n
Θ
)
B
=
(
3
+
4
c
o
s
(
Θ
+
2
π
3
)
,
−
5
+
4
s
i
n
(
Θ
+
2
π
3
)
)
C
=
(
3
+
4
c
o
s
(
Θ
+
4
π
3
)
,
−
5
+
4
s
i
n
(
Θ
+
4
π
3
)
)
The orthocentre of the triangle is (3, 5) Reason: consider
Δ
ABC whose verticies are A = (3 + 4 cos
Θ
,
−
5
+
4
s
i
n
Θ
)
B
=
(
3
+
4
c
o
s
(
Θ
+
2
π
3
)
,
−
5
+
4
s
i
n
(
Θ
+
2
π
3
)
)
C
=
(
3
+
4
c
o
s
(
Θ
+
4
π
3
)
,
−
5
+
4
s
i
n
(
Θ
+
4
π
3
)
)
The triangle ABC is equilateral
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