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Question

Find the equation of hyperbola. Whose axes are coordinate axes and the distance of one of its vertices from the foci are 3 and 1.

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Solution

REF.Image.
Given BSi=1,AS1=3
aea=1 __ (1) and 2a+ae=3 __ (2)
solving (1) and (2)
2a+ae=3
2ae2a=2
____________
3ae=5
ae=5/3
and
2a+ae=3
aea=1
____________
3a=2
a=2/3
Now, we know that
b2=a2(e21)
b2=25949=219.
Eqn of hyperbola is x2a2y2b2=19x249y22=1


1119202_1201761_ans_82ba78b48d5743679e4397fd1061a5fd.jpg

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