Question

Find the equation of line whose sum of intercepts on coordinate-axes is 10 and x-intercept exceeds y-intercept by 4.

Answer 1

Given,

x-intercept+y-intercept = 10 ..........(1)

Also, x-intercept = y-intercept + 4

x-intercept - y-intercept = 4 .........(2)

Solving 1 and 2, we get,

$x-intercept=7$ and $y-intercept=3$

Thus, equation of required line is

$\frac{x}{7}+\frac{y}{3}=1$

$3x+7y=21$