Given that axis is along the x axis,
So, equation of parabola is of from
y2=4ac or y2=−4ax
Since (5,3) is in 1st quadrant
So, the parabola will of the from
y2=4ax
Point (5,3) will satisfy the equation of
parabola
putting x=5,y=3 in equation
(3)2=4a(5)
y=20a
a=920
Hence equation of parabola,
putting value of a=920 is
y2=4×(920)×x
y2=95x
5y2=9x
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