Question

Find the equation of the circle, whose centre is (2, - 3) and radius is 5.

Answer 1

The equation of the circle having centre (2, -3) and radius 5, is $(x-2{)}^2+(y+3{)}^2=5^2[\because (x-h{)}^2+(y-k{)}^2=r^2]$

$x^2-4x+4+y^2+6y+9=25$

$x^2+y^2-4x+6y-12=0$