Question

Find the equation of the circle with
Centre (0,2) and radius 2

Answer 1

Here h = 0, k = 2 and r = 2
the equation fo circle is
$(x-h{)}^2+(y-k{)}^2=r^2\therefore (x-0{)}^2+(y-2{)}^2=(2{)}^2\Rightarrow x^2+y^2+4-4y=4x^2+y^2-4y=0$
Which is required equation of circle.