Question

Find the equation of the circle with centre $(3,5)$ and radius $6$

Answer 1

Since the centre of the circle is $(3,5)$ and its radius $6$

Then, the equation of the circle is

${(x-3)}^2+{(y-5)}^2=6^2$

$\Rightarrow {(x-3)}^2+{(y-5)}^2=36$

$\Rightarrow x^2-6x+9+y^2-10y+25-36=0$

$\Rightarrow x^2+y^2-6x-10y-2=0$