Find the equation of the directrix of the parabola $x^{2} - 4 x - 3 y + 10 = 0$ .

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Solution

general formula,

$(x - b)^{2} = 2 p (y - a)$

given,

$x^{2} - 4 x - 3 y + 10 = 0$

$x^{2} - 4 x + 4 - 4 - 3 y + 10 = 0$

$(x - 2)^{2} = 3 y - 6$

$(x - 2)^{2} = 3 (y - 2)$

$y = a - \frac{p}{2}$

$y = 2 - \frac{\frac{3}{2}}{2}$

$∴ y = \frac{5}{4}$

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Similar questions

The equation of the directrix of the parabola $x^{2} - 4 x - 3 y + 10 = 0$ is

y^{2} + 4 y + 4 x + 2 = 0

4 x^{2} - 4 x - 2 y + 3 = 0

(2, 5)

y = 3

y^{2} + 4 y + 4 x + 2 = 0

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