Question

Find the equation of the line cutting off intercepts $\frac{-5}{4}$ and $\frac{4}{5}$ on the $X$ and $Y$ axes respectively.

Answer 1

$X$-intercept$=a=\frac{-5}{4}$

$Y$-intercept$=b=\frac{4}{5}$

Equation of the line is $\frac{x}{a}+\frac{y}{b}=1$

$\frac{x}{\frac{-5}{4}}+\frac{y}{\frac{4}{5}}=1$

$\Rightarrow \frac{-4x}{5}+\frac{5y}{4}=1$

$\Rightarrow -16x+25y=20$

$\Rightarrow 16x-25y=-20$

$\therefore$ Equation of the line is $16x-25y+20=0$