Question

Find the equation to the straight line
(i) Cutting off intercepts 3 and 2 from the axes.
(ii) Cutting off intercepts − 5 and 6 from the axes.

Answer 1

(i) Here, a = 3, b = 2
So, the equation of the line is

$$\begin{gathered} \frac{x}{a}+\frac{y}{b}=1 \\ \Rightarrow \frac{x}{3}+\frac{y}{2}=1 \\ \Rightarrow 2x+3y-6=0 \end{gathered}$$

(ii) Here, a = $-$5, b = 6
So, the equation of the line is

$$\begin{gathered} \frac{x}{a}+\frac{y}{b}=1 \\ \Rightarrow \frac{x}{-5}+\frac{y}{6}=1 \\ \Rightarrow 6x-5y+30=0 \end{gathered}$$