Question

Find the equation of the line cutting off intercepts $\frac{2}{3}$ and $\frac{-1}{4}$ on the $X$ and $Y$ axes respectively.

Answer 1

$X$-intercept$=a=\frac{2}{3}$

$Y$-intercept$=b=\frac{-1}{4}$

Equation of the line is $\frac{x}{a}+\frac{y}{b}=1$

$\frac{x}{\frac{2}{3}}+\frac{y}{\frac{-1}{4}}=1$

$\Rightarrow \frac{3x}{2}-4y=1$

$\Rightarrow 3x-8y=2$

$\therefore$ Equation of the line is $3x-8y-2=0$