Find the equation of the line parallel to the line passing through $(5, 7)$ and $(2, 3)$ and having $x$ intercept as $- 4$

3 y = 4 x - 16

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4 y = 3 x - 16

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3 y = 4 x + 16

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4 y = 3 x + 16

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Solution

The correct option is C $3 y = 4 x + 16$
Slope of the given line $= \frac{y_{2} - y_{1}}{x_{2} - x_{1}} = \frac{7 - 3}{5 - 2} = \frac{4}{3}$
So the slope of the required line is $\frac{4}{3}$ .
One of the point on this line is $(- 4, 0)$ . Hence the equation of the line is $y - 0 = \frac{4}{3} (x + 4)$
$\Rightarrow 3 y = 4 x + 16$

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