Question

Find the equation of the line passing through (-3, 5) and perpendicular to the line through the points (2, 5) and (-3, 6).

Answer 1

Let A(2, 5) and B(-3, 6) be any two points

$\therefore$ Slope of $AB=\frac{6-5}{-3-2}=-\frac{1}{5}$

Since the required line is perpendicular to AB.

$\therefore$ Slope of required line m = 5.

Now the required line passing through point (-3, 5) having slope 5

$\therefore$ y - 5 = 5(x+ 3) $\Rightarrow$ y - 5 = 5x + 15

$\Rightarrow$ 5x - y + 20 = 0.