Question

Find the equation of the line which is passes through the points $(3,6)$ and $(-2,1)$.

Answer 1

Consider the given points.

$(3,6)$ and $(-2,1)$

We know that the equation of the line passes through two points

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

Therefore,

$y-6=\frac{1-6}{-2-3}(x-3)$

$y-6=\frac{-5}{-5}(x-3)$

$y-6=x-3$

$x-y+3=0$

Hence, this is the answer.