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Question

Find the equation of the line passing through :

(i) (0, 1) and (1, 2) (ii) (-1, -4) and (3, 0)

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Solution

(i) Let (0, 1) = (x1, y1) and (1, 2) = (x2, y2)

s l o p e space o f space t h e space l i n e equals fraction numerator 2 minus 1 over denominator 1 minus 0 end fraction equals 1

The required equation of the line is given by:

y - y1 = m(x - x1)

y - 1 = 1(x - 0)

y - 1 = x

y = x + 1

(ii) Let (-1, -4) = (x1, y1) and (3, 0) = (x2, y2)

s l o p e space o f space t h e space l i n e equals fraction numerator 0 plus 4 over denominator 3 plus 1 end fraction equals 1

The required equation of the line is given by:

y - y1 = m(x - x1)

y + 4 = 1(x + 1)

y + 4 = x + 1

y = x - 3


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