wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the equation of the line passing through :

(i) (0, 1) and (1, 2) (ii) (-1, -4) and (3, 0)

Open in App
Solution

(i) Let (0, 1) = (x1, y1) and (1, 2) = (x2, y2)

s l o p e space o f space t h e space l i n e equals fraction numerator 2 minus 1 over denominator 1 minus 0 end fraction equals 1

The required equation of the line is given by:

y - y1 = m(x - x1)

y - 1 = 1(x - 0)

y - 1 = x

y = x + 1

(ii) Let (-1, -4) = (x1, y1) and (3, 0) = (x2, y2)

s l o p e space o f space t h e space l i n e equals fraction numerator 0 plus 4 over denominator 3 plus 1 end fraction equals 1

The required equation of the line is given by:

y - y1 = m(x - x1)

y + 4 = 1(x + 1)

y + 4 = x + 1

y = x - 3


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Two Point Form of a Straight Line
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon