Find the equation of the line through $(- 2, 3)$ with slope $- 4$

2x + y + 5 = 0

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4x + y + 1 = 0

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4x - y + 5 = 0

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4x +y + 5 = 0

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Solution

The correct option is D
4x +y + 5 = 0

Here $m = - 4$ and given point is $(- 2, 3)$

Using slope-intercept form

Equation of the given line is

$(y - y_{1}) = m (x - x_{1})$

$y - 3 = - 4 (x + 2)$

$4 x + y + 5 = 0$

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