Find the equation of the line which has intercepts as $(3, 0)$ and $(0, - 3)$ .

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Solution

The equation of line in intercept form is $\frac{x}{a} + \frac{y}{b} = 1$
$⟹ \frac{x}{3} - \frac{y}{3} = 1 x - y = 3$

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Find the equation of the line which has intercepts as (3,0) and (0,−3).

The equation of line in intercept form is xa+yb=1⟹x3−y3=1x−y=3

Find the equation of the line which has intercepts as $(3, 0)$ and $(0, - 3)$ .

The equation of line in intercept form is $\frac{x}{a} + \frac{y}{b} = 1$
$⟹ \frac{x}{3} - \frac{y}{3} = 1 x - y = 3$