Question

Find the equation of the line, which makes intercepts $–3\text{and}2$ on the $x$ and $y$ axes respectively.

Answer 1

We know that equation of a line with $x-$intercept $=a$ and $y-$ intercept $=b$ can be written as
$\frac{x}{a}+\frac{y}{b}=1$
Here, $a=-3\text{and}b=2$

$\therefore$ Required equation of the line is
$\frac{x}{-3}+\frac{y}{2}=1$
$\Rightarrow 2x-3y+6=0$

Hence, the required equation is $2x-3y+6=0$