Find the equation of the line, whose slope $= 1$ and $y -$ intercept $= - 5$

y - x - 5 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

y - x + 5 = 0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

y + x - 5 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

y + x + 5 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $y - x + 5 = 0$
The equation of any straight line can be written as $y = m x + c$ , where $m$
is its slope and $c$ is its $y - i n t e r c e p t .$
Hence, the equation of the line with $s l o p e = 1$ and $y - i n t e r c e p t = - 5$
is $y = x - 5$ .

Suggest Corrections

Similar questions

Find the equation of the line, whose

slope

= 0

and

y -

intercept

= - 5

Find the equation of the lines through the point of intersection of the lines x-3y+1 = 0 and 2x+5y-9 = 0 and whose distance from the origin is $\sqrt{5}$ .

Q. Find the slope and y-intercept of the lines

x - y + 5 = 0

Q. Find the equation of the straight line that has y - intercept 5 and is parallel to the straight line x - 3y = 3

Reduce the following equations into slope-intercept form and find their slopes and the y-intercepts.

(i) x + 7y = 0 (ii) 6x + 3y – 5 = 0 (iii) y = 0

Join BYJU'S Learning Program

Find the equation of the line, whose slope =1 and y− intercept =−5

The correct option is B y−x+5=0The equation of any straight line can be written as y=mx+c, where mis its slope and c is its y−intercept. Hence, the equation of the line with slope=1 and y−intercept=−5is y=x−5.

Find the equation of the line, whose slope $= 1$ and $y -$ intercept $= - 5$

The correct option is B $y - x + 5 = 0$
The equation of any straight line can be written as $y = m x + c$ , where $m$
is its slope and $c$ is its $y - i n t e r c e p t .$
Hence, the equation of the line with $s l o p e = 1$ and $y - i n t e r c e p t = - 5$
is $y = x - 5$ .