Find the equation of the line, whose slope $= 3$ and $y -$ intercept $= 4$

y - 3 x + 4 = 0

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y - 3 x - 4 = 0

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y + 3 x + 4 = 0

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y + 3 x - 4 = 0

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Solution

The correct option is A $y - 3 x - 4 = 0$
The equation of any straight line can be written as $y = m x + c$ , where $m$
is its slope and $c$ is its $y$ - intercept.
Hence, the equation of the line with slope $= 3$ and y - intercept $= 4$
$y = m x + c$
$∴ y = 3 x + 4$
$∴ y - 3 x - 4 = 0$

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