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Question

Find the equation of the parabola with vertex at origin, symmetric with respect to yaxis and passing through (2,2)

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Solution

The vertex of the parabola is at origin and it is symmetric with respect to yaxis
Also, it passes through (2,2) , a point in the fourth quadrant.
Let its equation be x2=4ay ........(1)
As it passes through (2,2), we get
22=4a×2a=12
Substituting this value of a in (1), the equation of the parabola is
x2=4×12y
or x2=2y

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