Find the equation of the perpendicular bisector of the line segment joining points (7, 1) and (3,5).

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Solution

TO FIND: The equation of perpendicular bisector of line segment joining points (7, 1) and (3, 5)

Let P(x, y) be any point on the perpendicular bisector of AB. Then,

PA=PB

Hence the equation of perpendicular bisector of line segment joining points (7, 1) and (3, 5) is

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Find the equation of the perpendicular bisector of the straight line segment joining the points $(3, 4)$ and $(- 1, 2)$ .

A (2, 3)

B (6, - 5)

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