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Question

Find the equation of the perpendicular bisector of the straight line segment joining the points (3,4) and (1,2).


A

2y – x = 5

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B

y – x = 5

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C

y + 2x = 5

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D

3y – 2x = 5

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Solution

The correct option is C

y + 2x = 5


Midpoint of the points (3,4) and (1,2)

=(312,4+22)=(1,3)

Slope of a line joining points (3,4) and (1,2) =2413=12

Slope of the required line = 2

So, equation of required line is (y3)=(2)(x1)

y3=2x+2

2x+y5=0


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