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Question

# The equation of perpendicular bisector of the line segment joining the points (1,2) and (−2,0) is

A
5x+2y=1
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B
4x+6y=1
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C
6x+4y=1
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D
none of these
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Solution

## The correct option is A 6x+4y=1A(1,2) and B(−2,0) are given point ∴ midpoint p=(1+(−2)2,2+02)∴ midpoint p=(−12,1)Also slope of AB=0−(2)−2−1=−2−3∴ slope of AB=23slope of line perpendicular to AB=−123=−32∴ equation of perpendicular bisectory−1=−32(x+12)∴y−1=−32(x+12)∴2y−2=−3(x+12)∴4y−4=−3(2x+1)∴4y−4=−6x−3∴4y+6x−4+3=06x+4y−1=0∴ equation of line 6x+4y−1=0

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